-8x^2+160x+500=0

Solution for -8x^2+160x+500=0 equation:

-8x^2+160x+500=0

a = -8; b = 160; c = +500;
Δ = b2-4ac
Δ = 1602-4·(-8)·500
Δ = 41600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{41600}=\sqrt{1600*26}=\sqrt{1600}*\sqrt{26}=40\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-40\sqrt{26}}{2*-8}=\frac{-160-40\sqrt{26}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+40\sqrt{26}}{2*-8}=\frac{-160+40\sqrt{26}}{-16}
$